Optimal. Leaf size=157 \[ -\frac{14 e^{9/2} \text{EllipticF}\left (\sin ^{-1}\left (\frac{\sqrt{c e+d e x}}{\sqrt{e}}\right ),-1\right )}{15 d}-\frac{14 e^3 \sqrt{-c^2-2 c d x-d^2 x^2+1} (c e+d e x)^{3/2}}{45 d}-\frac{2 e \sqrt{-c^2-2 c d x-d^2 x^2+1} (c e+d e x)^{7/2}}{9 d}+\frac{14 e^{9/2} E\left (\left .\sin ^{-1}\left (\frac{\sqrt{c e+d x e}}{\sqrt{e}}\right )\right |-1\right )}{15 d} \]
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Rubi [A] time = 0.134437, antiderivative size = 157, normalized size of antiderivative = 1., number of steps used = 7, number of rules used = 6, integrand size = 37, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.162, Rules used = {692, 690, 307, 221, 1199, 424} \[ -\frac{14 e^3 \sqrt{-c^2-2 c d x-d^2 x^2+1} (c e+d e x)^{3/2}}{45 d}-\frac{2 e \sqrt{-c^2-2 c d x-d^2 x^2+1} (c e+d e x)^{7/2}}{9 d}-\frac{14 e^{9/2} F\left (\left .\sin ^{-1}\left (\frac{\sqrt{c e+d x e}}{\sqrt{e}}\right )\right |-1\right )}{15 d}+\frac{14 e^{9/2} E\left (\left .\sin ^{-1}\left (\frac{\sqrt{c e+d x e}}{\sqrt{e}}\right )\right |-1\right )}{15 d} \]
Antiderivative was successfully verified.
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Rule 692
Rule 690
Rule 307
Rule 221
Rule 1199
Rule 424
Rubi steps
\begin{align*} \int \frac{(c e+d e x)^{9/2}}{\sqrt{1-c^2-2 c d x-d^2 x^2}} \, dx &=-\frac{2 e (c e+d e x)^{7/2} \sqrt{1-c^2-2 c d x-d^2 x^2}}{9 d}+\frac{1}{9} \left (7 e^2\right ) \int \frac{(c e+d e x)^{5/2}}{\sqrt{1-c^2-2 c d x-d^2 x^2}} \, dx\\ &=-\frac{14 e^3 (c e+d e x)^{3/2} \sqrt{1-c^2-2 c d x-d^2 x^2}}{45 d}-\frac{2 e (c e+d e x)^{7/2} \sqrt{1-c^2-2 c d x-d^2 x^2}}{9 d}+\frac{1}{15} \left (7 e^4\right ) \int \frac{\sqrt{c e+d e x}}{\sqrt{1-c^2-2 c d x-d^2 x^2}} \, dx\\ &=-\frac{14 e^3 (c e+d e x)^{3/2} \sqrt{1-c^2-2 c d x-d^2 x^2}}{45 d}-\frac{2 e (c e+d e x)^{7/2} \sqrt{1-c^2-2 c d x-d^2 x^2}}{9 d}+\frac{\left (14 e^3\right ) \operatorname{Subst}\left (\int \frac{x^2}{\sqrt{1-\frac{x^4}{e^2}}} \, dx,x,\sqrt{c e+d e x}\right )}{15 d}\\ &=-\frac{14 e^3 (c e+d e x)^{3/2} \sqrt{1-c^2-2 c d x-d^2 x^2}}{45 d}-\frac{2 e (c e+d e x)^{7/2} \sqrt{1-c^2-2 c d x-d^2 x^2}}{9 d}-\frac{\left (14 e^4\right ) \operatorname{Subst}\left (\int \frac{1}{\sqrt{1-\frac{x^4}{e^2}}} \, dx,x,\sqrt{c e+d e x}\right )}{15 d}+\frac{\left (14 e^4\right ) \operatorname{Subst}\left (\int \frac{1+\frac{x^2}{e}}{\sqrt{1-\frac{x^4}{e^2}}} \, dx,x,\sqrt{c e+d e x}\right )}{15 d}\\ &=-\frac{14 e^3 (c e+d e x)^{3/2} \sqrt{1-c^2-2 c d x-d^2 x^2}}{45 d}-\frac{2 e (c e+d e x)^{7/2} \sqrt{1-c^2-2 c d x-d^2 x^2}}{9 d}-\frac{14 e^{9/2} F\left (\left .\sin ^{-1}\left (\frac{\sqrt{c e+d e x}}{\sqrt{e}}\right )\right |-1\right )}{15 d}+\frac{\left (14 e^4\right ) \operatorname{Subst}\left (\int \frac{\sqrt{1+\frac{x^2}{e}}}{\sqrt{1-\frac{x^2}{e}}} \, dx,x,\sqrt{c e+d e x}\right )}{15 d}\\ &=-\frac{14 e^3 (c e+d e x)^{3/2} \sqrt{1-c^2-2 c d x-d^2 x^2}}{45 d}-\frac{2 e (c e+d e x)^{7/2} \sqrt{1-c^2-2 c d x-d^2 x^2}}{9 d}+\frac{14 e^{9/2} E\left (\left .\sin ^{-1}\left (\frac{\sqrt{c e+d e x}}{\sqrt{e}}\right )\right |-1\right )}{15 d}-\frac{14 e^{9/2} F\left (\left .\sin ^{-1}\left (\frac{\sqrt{c e+d e x}}{\sqrt{e}}\right )\right |-1\right )}{15 d}\\ \end{align*}
Mathematica [C] time = 0.0798781, size = 86, normalized size = 0.55 \[ -\frac{2 e^3 (e (c+d x))^{3/2} \left (\sqrt{-c^2-2 c d x-d^2 x^2+1} \left (5 c^2+10 c d x+5 d^2 x^2+7\right )-7 \, _2F_1\left (\frac{1}{2},\frac{3}{4};\frac{7}{4};(c+d x)^2\right )\right )}{45 d} \]
Antiderivative was successfully verified.
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Maple [B] time = 0.205, size = 500, normalized size = 3.2 \begin{align*}{\frac{{e}^{4}}{90\,d \left ({x}^{3}{d}^{3}+3\,{x}^{2}c{d}^{2}+3\,x{c}^{2}d+{c}^{3}-dx-c \right ) }\sqrt{e \left ( dx+c \right ) }\sqrt{-{d}^{2}{x}^{2}-2\,cdx-{c}^{2}+1} \left ( -20\,{d}^{6}{x}^{6}-120\,{x}^{5}c{d}^{5}-300\,{x}^{4}{c}^{2}{d}^{4}-400\,{x}^{3}{c}^{3}{d}^{3}-8\,{d}^{4}{x}^{4}-300\,{x}^{2}{c}^{4}{d}^{2}-32\,{x}^{3}c{d}^{3}-120\,x{c}^{5}d+36\,\sqrt{2\,dx+2\,c+2}\sqrt{-dx-c}\sqrt{-2\,dx-2\,c+2}{\it EllipticE} \left ( 1/2\,\sqrt{2\,dx+2\,c+2},\sqrt{2} \right ){c}^{2}-36\,\sqrt{2\,dx+2\,c+2}\sqrt{-2\,dx-2\,c+2}\sqrt{dx+c}{\it EllipticE} \left ( 1/2\,\sqrt{-2\,dx-2\,c+2},\sqrt{2} \right ){c}^{2}-48\,{c}^{2}{d}^{2}{x}^{2}-20\,{c}^{6}-32\,x{c}^{3}d+15\,\sqrt{2\,dx+2\,c+2}\sqrt{-dx-c}\sqrt{-2\,dx-2\,c+2}{\it EllipticF} \left ( 1/2\,\sqrt{2\,dx+2\,c+2},\sqrt{2} \right ) +33\,\sqrt{2\,dx+2\,c+2}\sqrt{-dx-c}\sqrt{-2\,dx-2\,c+2}{\it EllipticE} \left ( 1/2\,\sqrt{2\,dx+2\,c+2},\sqrt{2} \right ) +15\,\sqrt{2\,dx+2\,c+2}\sqrt{-2\,dx-2\,c+2}\sqrt{dx+c}{\it EllipticF} \left ( 1/2\,\sqrt{-2\,dx-2\,c+2},\sqrt{2} \right ) +9\,\sqrt{2\,dx+2\,c+2}\sqrt{-2\,dx-2\,c+2}\sqrt{dx+c}{\it EllipticE} \left ( 1/2\,\sqrt{-2\,dx-2\,c+2},\sqrt{2} \right ) +28\,{d}^{2}{x}^{2}-8\,{c}^{4}+56\,cdx+28\,{c}^{2} \right ) } \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{{\left (d e x + c e\right )}^{\frac{9}{2}}}{\sqrt{-d^{2} x^{2} - 2 \, c d x - c^{2} + 1}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (-\frac{{\left (d^{4} e^{4} x^{4} + 4 \, c d^{3} e^{4} x^{3} + 6 \, c^{2} d^{2} e^{4} x^{2} + 4 \, c^{3} d e^{4} x + c^{4} e^{4}\right )} \sqrt{-d^{2} x^{2} - 2 \, c d x - c^{2} + 1} \sqrt{d e x + c e}}{d^{2} x^{2} + 2 \, c d x + c^{2} - 1}, x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{{\left (d e x + c e\right )}^{\frac{9}{2}}}{\sqrt{-d^{2} x^{2} - 2 \, c d x - c^{2} + 1}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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